![]() ZonedDateTime zdt = ZonedDateTime.parse ( input, formatter ) String input = "T15:00:08.868987" ĭateTimeFormatter formatter = DateTimeFormatter.ISO_LOCAL_DATE_TIME.withZone ( ZoneOffset.UTC ) In other words, no further time zone adjustment is made. That time zone is also assigned as the time zone of the ZonedDateTime object. We specify UTC as the time zone by calling withZone. So we must specify a time by which to interpret the meaning of that input. The first string has no time zone or offset-from-UTC info. You have two input strings, so two examples. For some formats we need not even bother specifying a formatter at all. So we can specify one of the predefined formatter rather than define a formatter pattern. The java.time classes use ISO 8601 by default when parsing or generating String representations of date-time values. ISO 8601īoth of your String inputs are in the formats defined by the ISO 8601 standard. The java.time classes support nanosecond resolution, up to 9 digits of fractional second. The new classes are inspired by the highly successful Joda-Time framework, intended as its successor, similar in concept but re-architected. The classes you are using, &, have been supplanted by the new java.time framework built into Java 8 and later. So even if you manage to parse that input, you will be losing some information. You are using the old class which supports only milliseconds (3 digits). You are parsing a string input with six digits of fractional second, which means microsecond. This correctly recognizes the UTC timezone and allows you to then use Joda Time's extensive manipulation methods to get what you want out of it. String timestamp = "" ĭateTime dateTime = ISODateTimeFormat.dateTimeParser().parseDateTime(timestamp) If you're stuck with Java 6 or earlier, the answer recommending JodaTime is a safe bet. SimpleDateFormat inFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssX") ![]() ![]() If date time is in ,then you can use pattern yyyy-MM-dd'T'HH:mm:ssX where X denotes ISO 8601 time zone.The Java 7 version of SimpleDateFormat supports ISO-8601 time zones using the uppercase letter X. SimpleDateFormat inFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS") If you just mark Z in single quotes,it will just consider as a String rather than parsing it. If time format is in above ,it will work fine. SimpleDateFormat inFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ") In the second example, we used the slash / between date parts to correctly convert from a string to the date data type.Reason is you are using wrong format,here Z represents timezone String s = "T18:46:19-0700" In Example 2, the string '7' was converted to the date ''. In Example 1, the string date as ‘ 20020304’ was converted to the date '' (a date data type. You can find a list of all specifiers in the PostgreSQL documentation. Next, ‘MM’ represents a 2-digit month and ‘DD’ a 2-digit day. The specifier ‘YYYY’ as the first four characters indicates that these represent a 4-digit year. The input format decides how PostgreSQL will process the characters in the string where the date is stored. Notice that the input format is a string. In our example, we used 'YYYYMMDD' and 'YYYY/MM/DD'. In our example, we used the strings '20020304' and '7'. This can be a string (a text value) or a text column containing date information. Use the function TO_DATE() to convert a text value containing a date to the date data type. SELECT TO_DATE('7', 'YYYY/MM/DD') AS new_date Notice the slightly different date format: Let’s look at Example 2 of the TO_DATE() function. SELECT TO_DATE('20020304', 'YYYYMMDD') AS new_date Īnd here’s the result of the query: new_date Here’s Example 1 of how to use the TO_DATE() function. ![]() Let’s convert a date string to the date data type instead of its current text data type. You’d like to convert a string containing a date to the PostgreSQL date data type. ![]()
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